Non Optional AppIntent Param

Question

megatron1000 OP

Created Sep ’24

Replies 2

Boosts 7

Participants 3

After building my app with Xcode 16 beta 6 I'm getting this warning in my AppIntents.

Encountered a non-optional type for parameter: computer. Conformance to the following AppIntent protocols requires all parameter types to be optional: AppIntents.WidgetConfigurationIntent, AppIntents.ControlConfigurationIntent

The intent looks something like this

struct WakeUp: AppIntent, WidgetConfigurationIntent, PredictableIntent {
    
    @Parameter(title: "intent.param.computer", requestValueDialog:"intent.param.request_dialog.computer")
    var computer: ComputerEntity

    init(computer: ComputerEntity) {
        self.computer = computer
    }
    
    init() {
        
    }
    
    public static var parameterSummary: some ParameterSummary {
        Summary("Wake Up \(\.$computer)")
    }

    static var predictionConfiguration: some IntentPredictionConfiguration {
        IntentPrediction(parameters: (\.$computer)) { computer in
            DisplayRepresentation(
                title: "Wake Up \(computer)"
            )
        }
    }

    @MainActor
    func perform() async throws -> some IntentResult & ProvidesDialog {

    }
}

According to the docs though specifying optional is how we say if the value is required or not. https://developer.apple.com/documentation/appintents/adding-parameters-to-an-app-intent#Make-a-parameter-optional-or-required

So is this warning accurate? If so, how do I specify that a parameter is required by the intent now?

Boost

Answer 1

Sonisan OP

Sep ’24

Same question here...

4

Answer 2

Buttercup OP

3w

You probably should declare two different intents: one with non-optional parameter and perform() function implementation; and another one that implements WidgetConfigurationIntent, has optional parameter, and no perform() function.

You'd also want to declare that second one as non-discoverable.

static let isDiscoverable = false

That approach worked well for me.

0