My guess is that Apple Watch doesn't support all the widths available yet.
Since the Apple Watch uses SF Compact, not SF Pro.
sarunw
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You can declare variable of Namespace.ID in a view to reference @Namespace from its parent. Here is an example.
struct ContentViewNameSpace: View {
		@State private var isExpanded = false
		@Namespace private var namespace
		
		
		var body: some View {
				Group() {
				if isExpanded {
						VerticalView(namespace: namespace)
				} else {
						HorizontalView(namespace: namespace)
				}
				}.onTapGesture {
				withAnimation {
						isExpanded.toggle()
				}
				}
		}
}
struct VerticalView: View {
		var namespace: Namespace.ID
		
		var body: some View {
				VStack {
				RoundedRectangle(cornerRadius: 10)
						.foregroundColor(Color.pink)
						.frame(width: 60, height: 60)
						.matchedGeometryEffect(id: "rect", in: namespace, properties: .frame)
				Text("Hello SwiftUI!").fontWeight(.semibold)
						.matchedGeometryEffect(id: "text", in: namespace)
				}
		}
}
struct HorizontalView: View {
		var namespace: Namespace.ID
		
		var body: some View {
				HStack {
				Text("Hello SwiftUI!").fontWeight(.semibold)
						.matchedGeometryEffect(id: "text", in: namespace)
				RoundedRectangle(cornerRadius: 10)
						.foregroundColor(Color.pink)
						.frame(width: 60, height: 60)
						.matchedGeometryEffect(id: "rect", in: namespace, properties: .frame)
				}
		}
}
I got state, code, and id_token (JWT). Where does Apple say that user object will be returned?