For example, in the code block below, why do we need to call it using
Int.hey(lhs: 5, rhs: 6), while the other one just define the operator in the same time?
Wouldn't it be confusing?
Will something like operator func hey(lhs: Self, rhs: Self) -> Self be clearer?
public protocol Multiplyable {
static func &(lhs: Self, rhs: Self) -> Self
static func hey(lhs: Self, rhs: Self) -> Self
}
extension Double: Multiplyable {
static public func &(lhs: Self, rhs: Self) -> Self {
return lhs * rhs
}
public static func hey(lhs: Self, rhs: Self) -> Self {
return lhs * rhs
}
}
extension Int: Multiplyable {
static public func &(lhs: Self, rhs: Self) -> Self {
return lhs * rhs
}
public static func hey(lhs: Self, rhs: Self) -> Self {
return lhs * rhs
}
}
let result1 = 3&4
print(result1)
let result2 = Int.hey(lhs: 5, rhs: 6)
print(result2)
allenlinli
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