Is using `static func` to define a operator confusing with normal `static func` functions?

For example, in the code block below, why do we need to call it using Int.hey(lhs: 5, rhs: 6), while the other one just define the operator in the same time? Wouldn't it be confusing? Will something like operator func hey(lhs: Self, rhs: Self) -> Self be clearer?

public protocol Multiplyable {
  static func &(lhs: Self, rhs: Self) -> Self
   
  static func hey(lhs: Self, rhs: Self) -> Self
}

extension Double: Multiplyable {
  static public func &(lhs: Self, rhs: Self) -> Self {
    return lhs * rhs
  }
   
  public static func hey(lhs: Self, rhs: Self) -> Self {
    return lhs * rhs
  }
}
extension Int: Multiplyable {
  static public func &(lhs: Self, rhs: Self) -> Self {
    return lhs * rhs
  }
   
  public static func hey(lhs: Self, rhs: Self) -> Self {
    return lhs * rhs
  }
}

let result1 = 3&4
print(result1)

let result2 = Int.hey(lhs: 5, rhs: 6)
print(result2)