simctl launch --console flag doesn't seem to work?

Question

Created Apr ’23

Replies 1

Boosts 1

Participants 2

I created a simple app in Xcode. Installed and ran it in the iOS Simulator. I can also start it from command line like this:

% xcrun simctl launch booted com.example.TestBuildCommands --console
com.example.TestBuildCommands: 52877
%

It just prints that one line and returns my shell prompt. But the help for launch says that --console should: "Block and print the application's stdout and stderr to the current terminal."

In my main() function I have:

int main(int argc, char * argv[]) {
    printf("In main.\n");
    ...

Shouldn't I be seeing that message in my terminal screen?

% xcrun simctl help launch                                               
Launch an application by identifier on a device.
Usage: simctl launch [-w | --wait-for-debugger] [--console|--console-pty] [--stdout=&lt;path>] [--stderr=&lt;path>] [--terminate-running-process] &lt;device> &lt;app bundle identifier> [&lt;argv 1> &lt;argv 2> ... &lt;argv n>]

	--console Block and print the application&#039;s stdout and stderr to the current terminal.
		Signals received by simctl are passed through to the application.
		(Cannot be combined with --stdout or --stderr)
    [...]

ps. Anyone know how to turn off syntax highlighting in those triple-backquoted code blocks that are meant to be just terminal text, not highlighted code?

Boost

Answer 1

jalopezg OP

Mar ’24

Hi @rnikander,

Per simctl help launch usage message, all arguments that are passed after the <bundle identifier> are directly passed to the spawned application (I guess via usual argv[] vector). --console should thus be specified before the bundle identifier, as in.

% xcrun simctl launch --console booted com.example.TestBuildCommands

Cheers, Javier.

0