I need to make 2 API calls simultaneously. I have 2 URLs for the calls, and if one of the calls will return any error I want to stop all the code execution.
How I tried to do it:
I have a function called performRequest()
with a completion block. I call the function in my ViewController
to update the UI - show an error/or a new data if all was successful. Inside it I create a URLSession
tasks and then parse JSON:
I created an array with 2 urls:
func performRequest(_ completion: @escaping (Int?) -> Void) {
var urlArray = [URL]()
guard let urlOne = URL(string: "https://api.exchangerate.host/latest?base=EUR&places=9&v=1") else { return }
guard let urlTwo = URL(string: "https://api.exchangerate.host/2022-05-21?base=EUR&places=9") else { return }
urlArray.append(urlOne)
urlArray.append(urlTwo)
}
Then for each of the url inside the array I create a session and a task:
urlArray.forEach { url in
let session = URLSession(configuration: .ephemeral)
let task = session.dataTask(with: url) { data, _, error in
if error != nil {
guard let error = error as NSError? else { return }
completion(error.code)
return
}
if let data = data {
let printData = String(data: data, encoding: String.Encoding.utf8)
print(printData!)
DispatchQueue.main.async {
self.parseJSON(with: data)
}
}
}
task.resume()
}
print("all completed")
completion(nil)
}
For now I receive print("all completed")
printed once in any situation: if both tasks were ok, if one of them was ok or none of them.
What I want is to show the print statement only if all tasks were completed successfully and to stop executing the code if one of them returned with error (for example if we will just delete one of the symbols in url string which will take it impossible to receive a data).
How can I do it correctly?