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Reply to SwiftUI: Can't Show view
@Claude31 this full code import CoreLocation import SwiftUI struct ContentView: View {   @ObservedObject var detector = BeaconDetector()   @EnvironmentObject var popupManager: PopupManager   @EnvironmentObject var authViewModel: AuthViewModel   @State var isNavigationBarHidden: Bool = true   @State var isShowAlert = true   @State var showDetail = false   var artworkinfo: Artworkinfo   var exhibition: Exhibition //  var artwork: Artwork   @StateObject var artwork = ArtworkViewModel()   @State private var showSecondView = false   var body: some View {     VStack {       Group {         // no logged in         if authViewModel.userSession == nil {           LoginView()         } else {           // logged in user           if detector.lastDistance == .immediate {             if showDetail == false {               Text("")                 .alert(isPresented: $isShowAlert) {                   Alert(                     title: Text("Hi! Art Lovers"),                     message: Text("We want to help you find your nearest Artwork 🖼️"),                     dismissButton:                     .default(Text("OK"),                          action: {                            self.showDetail = true                          }                     )                   )                 }             } else {               let getArtwork = artwork.artworks.filter { $0.id == "1" }.first               if getArtwork?.uuidbeacon == BeaconDetector.getBeaconID() {                 NavigationLink(destination: ArtworkInfoBeacon(artwork: getArtwork!), isActive: self.$showDetail) {                   ArtworkInfoBeacon(artwork: getArtwork!)                 }               }             }           } else {             mainInterfaceView           }         }       } // Group     } // vStack   } // some view //  func alertDetector() -> EmptyView { //    showDetail = false //    return EmptyView() //  } } struct ContentView_Previews: PreviewProvider {   static var previews: some View {     ContentView(artworkinfo: Artworkinfo(       id: 0,       atwName: "Anthropocene",       atwArtist: "Sirawich",       ateCate: "Painting",       atwDesc: "It is a long established fact that a reader will be distracted by the readable content of a page when looking at its layout. The point of using Lorem Ipsum is that it has a more-or-less normal",       atwSound: "mp4",       atwImg: "AnthropoceneCover",       idExhbt: 0), exhibition: Exhibition(id: "", exhbtstate: "", exhbtname: "", exhbtstr: "", exhbtend: "", exhbtdesc: "", timestr: "", timeend: "", exhbtorgnz: "", loctname: "", loctdetail: "", ticket: "", imgcover: ""), artwork: ArtworkViewModel())   } } extension ContentView {   var mainInterfaceView: some View {     VStack {       MainTabView()     }   } }
Mar ’23
Reply to SwiftUI, Firestore getting one collection and matching with another
Edit: now i found error, Thanks for help me ForEach<Array, String, Optional<NavigationLink<ArtworkInfoCard, ArtworkInfoView>>>: the ID 1 occurs multiple times within the collection, this will give undefined results! ForEach<Array, String, Optional<NavigationLink<ArtworkInfoCard, ArtworkInfoView>>>: the ID 1 occurs multiple times within the collection, this will give undefined results! ForEach<Array, String, ForEach<Array, String, Optional<NavigationLink<ArtworkInfoCard, ArtworkInfoView>>>>: the ID 2 occurs multiple times within the collection, this will give undefined results! ForEach<Array, String, ForEach<Array, String, Optional<NavigationLink<ArtworkInfoCard, ArtworkInfoView>>>>: the ID 1 occurs multiple times within the collection, this will give undefined results! LazyVGridLayout: the ID UniqueID(value: 4196) is used by multiple child views, this will give undefined results!
Jan ’23