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I am developing an app which should run on Ipad, Iphone and Mac. From the app the user shall be able to press a button and copy a result (pure text) into the clipboard so it can be pasted into other apps on the same device (command + V). This works fairly well on my Ipad (or Iphone) where I use this (IOS) code: import SwiftUI import UniformTypeIdentifiers ..... UIPasteboard.general.setValue(output, forPasteboardType: UTType.plainText.identifier) .... The problem is that when I run this on "My Mac (Designed for iPad) - it does not copy the text when run on Mac as compatible iPad app. I take note that to access the clipboard on MacOS you would need another (MacOS) code like this. import Cocoa ... let pasteboard = NSPasteboard.general() pasteboard.declareTypes([NSPasteboardTypeString], owner: nil) pasteboard.setString(output, forType: NSPasteboardTypeString) .... The problem is that Cocoa can only be imported into native MacOS app - and while I recognise this could be handled with a lot of pre-processor statements separating native IOS and native MacOS code - it would highly complicate my code - and I would almost need to write the app twice just switching all the UI's to NS's. #if os(iOS) UIPasteboard.general.setValue(output, forPasteboardType: UTType.plainText.identifier) #elseif os(macOS) let pasteboard = NSPasteboard.general() pasteboard.declareTypes([NSPasteboardTypeString], owner: nil) pasteboard.setString(output, forType: NSPasteboardTypeString) #endif Even for the clipboard example it would start to complicate things. Then add to this that have have several references to other UI-classes which would be NS-classes on a MacOS. Can this be handled in a smarter way now we actually can run SwiftUI and IOS apps on a Mac???? I know one way could be to copy my output into a text-field from which the user could "Command + C" - but it is really not what I want. I hope there is something clean and smart for this - so we can assume that IOS apps can actually run on Mac with full compatibility. Thanks in advance
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by Westerlin.
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