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Hi,i have been trying out SwiftUI Table and wanted to present a details view when click on Table Row occurs, but I couldn't figure out how to "deselect" row once its been selected, while it may not be what Table was intended for, but I still think this code should be valid. (iPadOS) struct Person: Identifiable { let givenName: String let familyName: String let emailAddress: String let id = UUID() } private var people = [ Person(givenName: "Juan", familyName: "Chavez", emailAddress: "juanchavez@icloud.com"), Person(givenName: "Mei", familyName: "Chen", emailAddress: "meichen@icloud.com"), Person(givenName: "Tom", familyName: "Clark", emailAddress: "tomclark@icloud.com"), Person(givenName: "Gita", familyName: "Kumar", emailAddress: "gitakumar@icloud.com") ] @State private var selectedPeople: Person.ID? @State private var detailsViewPresented: Bool = false var body: some View {         Table(people, selection: $selectedPeople) {             TableColumn("Given Name", value: \.givenName)             TableColumn("Family Name", value: \.familyName)             TableColumn("E-Mail Address", value: \.emailAddress)         }         .onChange(of: selectedPeople) { selection in             guard selection != nil else {                 return             }             detailsViewPresented = true         }         .sheet(isPresented: $detailsViewPresented, onDismiss: {             // Trying to reset the selection             self.selectedPeople = nil         }) {             Text("Person's details")         } } Here when I press row, it gets selected and Text is presented, but row still remains selected, and yes, I could just use onTapGesture within row content if I declared TableColumn with explicit content, but it would just be added to that column and would not provide build in selection style. https://developer.apple.com/documentation/swiftui/table