Unexpected linefeed?

Whence the linefeed plus () ?

Your usage of `print` outputs both.

Do you know that when you write `print(expr)`, `expr` is evaluated and then the result of evaluation is printed with a following newline as terminator.

So, in your line of code:

print(printTaxed2(pretax:150, taxrate: 4/3))

First, `printTaxed2(pretax:150, taxrate: 4/3)` is evaluated. While its evaluation, `200.0` is printed with terminator.

And the result of the evaluation is void value, as you declare the function `printTaxed2(pretax:taxrate:)` as a void function.

When a void value given, the `print` outputs `()` with terminator.

Generally, you should not write a void function call as a parameter for `print`, unless you want to see the void value `()`.

OK, thank you - I don't fully understand what you are saying, but it gives me something to work to.

I'll try

var anotherVariable = pretax*taxrate

print (anotherVariable)

Must admit, I'm groping in the dark rather!

Light dawns!

print(printTaxed2(pretax:150, taxrate: 4/3))

print(printTaxed2(pretax:150, taxrate: 1.3333))

has a surplus print command.

printTaxed2(pretax:150, taxrate: 4/3)

printTaxed2(pretax:150, taxrate: 1.3333)

doesn't, and works as it should.

Dear me, error spotting needs improvement!

A good way to improve your skills in such a case is to use debugger and go step by step (function key F6), after setting a breakpoint at the beginning (here at print(printTaxed2(pretax:150, taxrate: 4/3)))

You will see which statement precisely print the ()

Thanks, I'll try that.