NSTableView register cell for reuse

Question

Hi,

Recently, i started to develop an application for OS X with swift 4.2 with a minimal style programming (without nibs and xibs).

Surprisingly, i found that i can't register for reuse a view without a nib file for views in this tableView.

So I understand that my cells are not reuse and allways create a new instance of this, lowering the performance of the application.

Is there any way to reuse a class like in NSCollectionView?

Thanks for all.

1.7k

Posted by

Shargo

Reply

Answer 1

In IOS, you can register the cell class

func register(_ cellClass: AnyClass?, forCellReuseIdentifier identifier: String)

But effectively, seems that does not exist for OSX TableView (contrary to CollectionViews), need to register the nib

func register(_ nib: NSNib?, forIdentifier identifier: NSUserInterfaceItemIdentifier)

What I do usually in OSX Apps is to call

if let cellView = tableView.makeView(withIdentifier: NSUserInterfaceItemIdentifier(rawValue: "CellID"), owner: self)

in

func tableView(_ tableView: NSTableView, viewFor tableColumn: NSTableColumn?, row: Int) -> NSView? {

Not sure it has any noticeable impact on performance.

Posted by

Claude31

Answer 2

In IOS, you can register the cell class

func register(_ cellClass: AnyClass?, forCellReuseIdentifier identifier: String)

But effectively, seems that does not exist for OSX TableView (contrary to CollectionViews), need to register the nib

func register(_ nib: NSNib?, forIdentifier identifier: NSUserInterfaceItemIdentifier)

What I do usually in OSX Apps is to call

if let cellView = tableView.makeView(withIdentifier: NSUserInterfaceItemIdentifier(rawValue: "CellID"), owner: self)

in

func tableView(_ tableView: NSTableView, viewFor tableColumn: NSTableColumn?, row: Int) -> NSView? {

Not sure it has any noticeable impact on performance.

Posted by

Claude31

Accepted Reply