(ForEach-Error)SwiftUI, Firestore getting one collection and matching with another

Question

srthploid OP

Created Jan ’23

Replies 3

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Views 1.3k

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I am so confused with linking one collection to another (Foreach)

I want my artwork to be displayed in that exhibition. if collection: exhibition.id = collection: artwork.exhbtid show: infomation artwork (Infoview)

Any feedback would be appreciated. Thanks

Edit: now i found error I don't know what to do, Could you advise me

ForEach<Array, String, Optional<NavigationLink<ArtworkInfoCard, ArtworkInfoView>>>: the ID 1 occurs multiple times within the collection, this will give undefined results!

ForEach<Array, String, ForEach<Array, String, Optional<NavigationLink<ArtworkInfoCard, ArtworkInfoView>>>>: the ID 2 occurs multiple times within the collection, this will give undefined results!

ForEach<Array, String, ForEach<Array, String, Optional<NavigationLink<ArtworkInfoCard, ArtworkInfoView>>>>: the ID 1 occurs multiple times within the collection, this will give undefined results!

LazyVGridLayout: the ID UniqueID(value: 4196) is used by multiple child views, this will give undefined results!

Code: Screen Shot 2566-01-18 at 12.30.30.png

Exhibition Model: Screen Shot 2566-01-17 at 16.46.21.png

Exhibition ViewModel: Screen Shot 2566-01-17 at 16.46.03.png

Artwork Model: Screen Shot 2566-01-17 at 16.46.27.png

Artwork ViewModel: Screen Shot 2566-01-17 at 16.46.11.png

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Answer 1

MarcoCarnevali OP

Jan ’23

Hello. I'll try to address the error reported by the compiler first. As stated on Apple List documentation the List type should conform to Identifiable. This is done as SwiftUI needs to know how to identify each and every cell in our list in order to optimize it and perform any operation like displaying, removing cells.

That being said it seems by the error you reported that multiple cells have the same id. This is not acceptable since by design the id needs to be different for each cell. This is so SwiftUI can understand which cell is which. I would advise to double-check that the id is different in each Artwork type.

In the example below we assign a new unique UUID so that it's almost fully guaranteed that each cell have a different id:

struct Artwork: Identifiable {
    let id = UUID()
}

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Answer 2

srthploid OP

Jan ’23

I tried to do what was suggested from MarcoCarnevali (Thank you very much for your help.), But the program still doesn't work as I want. Any feedback would be appreciated. Thanks

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Answer 3

MarcoCarnevali OP

Jan ’23

@srthploid, what's the error (if any) reported by the compiler?

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