import SwiftUI
struct ButtonUI: View {
var body: some View {
ZStack {
Color.white
RoundedRectangle(cornerRadius: 50)
.fill(.blue)
.frame(width: 250, height: 75, alignment: .center)
Text("Enable Location")
.font(.title3)
.fontWeight(.bold)
.foregroundColor(Color.white)
}
.offset(x: 0, y: 300)
}
}
struct ButtonUI_Previews: PreviewProvider {
static var previews: some View {
ButtonUI()
}
}
// I have used this code to create a button like shape in Xcode how to do i make it work like open the location settings in iPhone
// it should work like a button to open the location settings in iPhone
What do you mean precisely by location settings
You can access your app's settings page URL from the UIApplication.openSettingsURLString
property.
Use it like this:
Button("Open Settings") {
// Get the settings URL and open it
if let url = URL(string: UIApplication.openSettingsURLString) {
UIApplication.shared.open(url)
}
}
There is currently no way to deep link directly to your app's location settings.
iOS 16 did, however, introduce a UIApplication.openNotificationSettingsURLString
property for the notifications settings section, so maybe the location settings URL is possible in the future, or through this.
I need a button in my app , when i click that button it should open the iPhone settings app and automatically navigate through the location settings