Filtering an Array

Question

WeagleWeagle OP

Created Jun ’22

Replies 3

Boosts 0

Views 1.1k

Participants 4

I'm trying to filter an array containing Recipes that have a property called title of type String that is required.

These are the variables used in the line of code:

@State private var searchingFor = ""
@State private var filteredRecipes = [Recipe]()

This is the line of code giving me the error:

filteredRecipes=filteredRecipes.filter{$0.title.contains(searchingFor)}

The error: "Value of optional type 'String?' must be unwrapped to refer to member 'contains' of wrapped base type 'String'"

Any ideas on how I need to rewrite that line of code so that I don't get that error? ie. how do I unwrap 'String?'

Answered by Claude31 in 717060022

When you post a question, please provide complete information (it may appear in another post, but we usually don't know).

How is Recipe defined ? Is title an optional String?

If so, you get the error.

To correct:

filteredRecipes = filteredRecipes.filter{($0.title ?? "").contains(searchingFor)}

Or is searchingFor an optional ? It may be if result or a query for instance.

If so, change to:

filteredRecipes = filteredRecipes.filter{$0.title.contains(searchingFor ?? "")}

Boost

Answer 1

Claude31 OP

Jun ’22

Accepted Answer

When you post a question, please provide complete information (it may appear in another post, but we usually don't know).

How is Recipe defined ? Is title an optional String?

If so, you get the error.

To correct:

filteredRecipes = filteredRecipes.filter{($0.title ?? "").contains(searchingFor)}

Or is searchingFor an optional ? It may be if result or a query for instance.

If so, change to:

filteredRecipes = filteredRecipes.filter{$0.title.contains(searchingFor ?? "")}

0

Answer 2

Scott OP

Jun ’22

it says the title is a string that is not optional

But the compiler disagrees, as the error message basically says the title property is an Optional<String>. Can you show the definition of the Recipe type?

0

Answer 3

artecolote OP

Jun ’22

just force unwrap your title since it is required for Recipe it should be safe

filteredRecipes=filteredRecipes.filter{$0.title!.contains(searchingFor)}

but it would be better if you define the property title as not optional instead.

1