Xcode 12.4: Image Literal returns error message

Question

pmdenlinger OP

Created Apr ’21

Replies 26

Boosts 5

Views 24k

Participants 44

I have tried to use the Image Literal on Xcode 12.4, and entered the following code:

Code Block diceImageView1.imageView?.image = imageLiteral(resourceName: "DiceSix")

but it returns an error message which says:

Code Block Value of type 'UIImageView' has no member 'imageView'

This error message prevents me from completing the build.

Any suggestions on how to handle this error?

Boost

Answer 1

Claude31 OP

Apr ’21

You didn't tell what diceImageView1 is, but I understand it is an UIImageView.
Right ?

If so, you should write:

Code Block diceImageView1.image =

then type

Code Block image lit

and auto completion will propose to choose "DiceSix"
To choose image, you can open library / Media, from the View Menu in Xcode.

May be you need ? optional chaining, depending on the definition of diceImageView1

This will explain more: https://stackoverflow.com/questions/51397347/xcode-10-image-literals-no-longer-available

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Answer 2

pmdenlinger OP

Apr ’21

Thank you for your suggestion; I will give it a try.

I am following a course on learning Swift (I'm new to it); and the answer the teacher of the course is here: Xcode view controller

Have there been changes made to Swift and/or Xcode since she posted her solution?

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Answer 3

Claude31 OP

Apr ’21

You can type effectively #imageLiteral

But the code was with diceImageView1.image:

Code Block diceImageView1.image = #imageLiteral(resourceName: "DiceSix")

Don't forget to close the thread if that's OK now.

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Answer 4

pmdenlinger OP

Apr ’21

I just found that the solution is:

Code Block diceImageView1?.image = Image Literal

because diceImageView1 is already a UIImageView

This is my first experience with optionals in Swift.

Thank you.

1

Answer 5

southpawcoder OP

Sep ’21

image literal seems to not be working any further in Xcode 13. Does anybody know what's going on?

2

Answer 6

CPiyabootr OP

Oct ’21

Hi, I searched the Web and found the temporary fix for this .

 diceImageView1.image = UIImage(named: "DiceSix")   
 diceImageView2.image = UIImage(named: "DiceTwo")

You might need to play around with the brackets " ( " ( delete them and putting them back and see what happen. Xcode is being naughty sometimes. ). I reloaded my Project by recloned it again from Github and started the same procedures over. It seemed to work for me. However, for the following lessons where you will have to put these images in the arrays, I will need to try and perhaps search for solutions otherwise the line of code will be very long. If you have the solutions, I would appreciate if you can share.

Rick

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Answer 7

CPiyabootr OP

Oct ’21

Hi, I found this from Udemy Lesson Q&A from a user name LEE. This solution works for those of us who just starting to learn Swift. Thank you to LEE and would like his permission to share his answer below. Thanks again Lee.

Rick

Hi @Oleksandr,

I had the same issue with Xcode 13 also as it wasn't coming up in the dictionary suggestions when typing 'image literal'.

I've found that if you type the following then it will work and present you with the image icon and let you select the image as Angela has shown:

diceImageView1.image = #imageLiteral(

As soon as you type the trailing '(' then it will change to an image icon and let you select the DiceSix image.

Hope that helps!

Cheers,

Lee

1

Answer 8

stoicpushkar OP

Oct ’21

If you are following Angela Yu's Course, Here is how to fix the problem.

Type

#imageLiteral(

and the Xcode will auto-complete.

Screenshot 2021-10-14 at 12.48.05 PM.png

Note

Make sure the "L" is capital in Literal.

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Answer 9

RealLondoner OP

Oct ’21

Hi. Yes, I can agree. All you need is to type

diceImageView1.image = #imageLiteral(

then you will see a desirable symbol.

6

Answer 10

JPeters6060 OP

Nov ’21

Hi,

I typed diceImageView1.image = #imageliteral and it doesn't work for me

1

Answer 11

DragosO OP

Dec ’21

Instead of typing imageLiteral and let Xcode autocomplete the code, you can copy and paste this:

#imageLiteral(

P.S With the open bracket

Once you paste it after the "=" it will work

e.g

diceImageView1.image = #imageLiteral(

1

Answer 12

JenV OP

Dec ’21

Thanks CPiyabootr for the posting the answer. I am using XCode 13.1, imageLiteral by itself no longer works.

#imageLiteral( has to be typed out INSTEAD of typing imageLiteral and selecting the first choice as expressed in the Udemy course.

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Answer 13

haganjonathan42 OP

Jan ’22

To be on the safer side make sure to type the code complete like this

diceImageView1.image = #imageLiteral()

0

Answer 14

nikomamu OP

Jan ’22

yes it works when you need one image, diceImageView1.image = #imageLiteral( but when you need array of images this is not working , there is a problem

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Answer 15

whiskeyhotelpreston OP

Jan ’22

If you're following the Udemy Course for the Dicee-ios13 project use #imageLiteral( then press enter. This will allow you to select the image "DiceSix". This is running with latest version of Xcode (13.2.1).

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