How do I use reserved keyword `Type` in Swift?

Question

Diuming OP

Created Dec ’20

Replies 2

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Views 1.1k

Participants 2

I know, It doesn’t make sense. but I have no choice.
There are 2 problems

Code Block // problem1
let type = ReservedKeyword.`Type`(rawValue: 1)
public class ReservedKeyword: Codable {
    public enum `Type`: Int, Codable {
        case zero = 0
        case one = 1
        case two = 2
        case three = 3
    }
    public var type: ReservedKeyword.`Type`
    
    public init(type: ReservedKeyword.`Type`) {
        self.type = type
    }
    
    private enum CodingKeys: String, CodingKey {
        case type
    }
    public required init(from decoder: Decoder) throws {
        let container = try decoder.container(keyedBy: CodingKeys.self)
        // problem2
        self.type = try container.decode(ReservedKeyword.`Type`.self, forKey: .type)
    }
    public func encode(to encoder: Encoder) throws {
        var container = encoder.container(keyedBy: CodingKeys.self)
        try container.encode(self.type, forKey: .type)
    }
}

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Answer 1

OOPer OP

Dec ’20

An interesting example.

My best recommendation as for now is that avoid using the identifier Type and send a bug report to bugs.swift.org .

I have no choice.

If you mean you cannot change the identifier Type, typealias might be a workaround for problem 1.

Code Block typealias Type = ReservedKeyword.`Type`
let type = Type(rawValue: 1)

For problem 2, you can use non-prefixed type name:

Code Block     public required init(from decoder: Decoder) throws {
        let container = try decoder.container(keyedBy: CodingKeys.self)
        // problem2
        self.type = try container.decode(`Type`.self, forKey: .type)
    }

I'm not sure such workarounds would work in all future versions of Swift compilers. Better send the bug report soon.

0

Answer 2

Diuming OP

Dec ’20

@OOPer.
Thanks for help. It works.

0