“escape-sequence” in documentation

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Created Aug ’20

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In the swift official documentation: "the swift programming language"-"LANGUAGE REFERENCE"-"Lexical Structure"-"String Literals"-"GRAMMAR OF A STRING LITERAL".

It says:
escape-sequence → \ extended-string-literal-delimiter

and

"extended-string-literal-delimiter →

extended-string-literal-delimiter opt"

I think:
escape-sequence SHOULD → \ NOT → \ extended-string-literal-delimiter

Am I right? Thanks in advance.

Answered by OOPer in 625229022

As far as I checked, there are many incorrect parts in the Lexical Structure section, and I think escape-sequence should be:

escape-sequence → \ extended-string-literal-delimiter opt

When you write a String literal like ###"..."###, \### is a valid escape sequence.

Code Block let str = ###"abc\r\n\###r\###n"###

is equivalent to:

Code Block let str = "abc\\r\\n\r\n"

You should better check this article:
Behind the Proposal — SE-0200 Enhancing String Literals Delimiters to Support Raw Text

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Answer 1

OOPer OP

Aug ’20

Accepted Answer

As far as I checked, there are many incorrect parts in the Lexical Structure section, and I think escape-sequence should be:

escape-sequence → \ extended-string-literal-delimiter opt

When you write a String literal like ###"..."###, \### is a valid escape sequence.

Code Block let str = ###"abc\r\n\###r\###n"###

is equivalent to:

Code Block let str = "abc\\r\\n\r\n"

You should better check this article:
Behind the Proposal — SE-0200 Enhancing String Literals Delimiters to Support Raw Text

0

Answer 2

test1229 OP

Aug ’20

I get it, thank you very much.

0