Endian of ARGB2101010 in vImageConvert

Hi,

I'd like to understand vImageConver for ARGB2101010. Please help me about endianness.

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vImageConvert_ARGB16UToARGB2101010

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vImageConvert_ARGB16UToXRGB2101010

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vImageConvert_ARGB2101010ToARGB16U

Under header they show it is "little endian" a.k.a. "host endian".

Accelerate.framework/Frameworks/vImage.framework/Headers/Conversion.h
10171  This format is 10-bit little endian 32-bit pixels. The 2 MSB are zero.

But if I understand correctly, described pseudo code in header shows big endian to host endian conversion.

(read in ARGB2101010)

10180  The per-pixel operation is:
10181  @code
10182  uint32_t *srcPixel = src.data;
10183  uint32_t pixel = ntohl(srcPixel[0]);
10184  srcPixel += 1;

On the other hand, described pseudo code in header seems to run in "host endian", in other word "little endian".

(write out ARGB2101010)

10303  uint32_t *destPixel = dest.data;
10304  destPixel[0] = (A2 << 30) | (R10 << 20) | (G10 << 10) | (B10 << 0);
10305  destPixel += 1;
10306  @endcode

If the header doc is correct, vImage runs as "Reading in BigEndian and Writing in HostEndian".

There should be some inconsistencies.

Please tell me how to use these APIs.