As I was watching WWDC19 Session: "LLDB: beyond "po" " I got confused about "p" command. In the session there was a following example to show how "p" command works: // Struct for demonstration purposes struct Trip { var name: String var destinations: [String] let cruise = Trip ( name: "Mediterranean Cruise" destinations: ["Sorrento", "Capri", "Taormina"]) Using "p" to get info about cruise instance: (lldb) p cruise (Travel.Trip) $R0 = { name = "Mediterranean Cruise" destinations = 3 values { [0] = "Sorrento" [1] = "Capri" [2] = "Taormina" } } I was following along and wrote the same code. But the output from LLDB turned out to be different: (lldb) p cruise (LLDB_Apple_Session_FollowAlong.Trip) { name = "Mediterranean Cruise" destinations = 3 values { [0] = "Sorrento" [1] = "Capri" [2] = "Taormina" } } As you can see LLDB didn't create a global variable R0 which I could later use in my debugging session and that seemed strange to me. Then the presenter said the following: "p" is just an alias for the "expression" command. So, I tried to use the "expr" command to see if they're actually the same and they turned out to be different commands. The output I got from "expr" was the one I expected from "p": (lldb) expr cruise (LLDB_Apple_Session_FollowAlong.Trip) $R0 = { name = "Mediterranean Cruise" destinations = 3 values { [0] = "Sorrento" [1] = "Capri" [2] = "Taormina" } } Finally, my question is: Am I wrong somewhere or did something change in LLDB regarding "p" and "expr" commands and if so, where could I get more information about the changes?